TOOLS & RESOURCES

Axial Stiffness of Ball Screw Drives Across Nut Positions

Published:2026-11-10 00:00:00

Updated:

Axial stiffness · Parallel paths · Nut position

Follow the load path through the complete axis

The same thrust can produce a different displacement at another working position. Modeling shaft segments, supports, nut and joints with the correct series and parallel relationships separates position effects from structural improvements.

Ball screw drive axial stiffness illustration
Editorial illustration; real product references identify the structure, while the equivalent model and assumed values are defined in the article.

01 / What is being evaluated

Define the load, measurement point and reference

The same feed axis can show different elastic displacement when the same thrust is applied near the axial locating end and farther away. The screw is elastic, but position also changes the loaded shaft length and the relationship between supports and joints. A nut-stiffness value alone rarely explains the response of the complete axis.

This article evaluates quasi-static, small incremental displacement along the screw axis. The reference is the common rigid structure supporting the end assemblies, and the rotational coordinate is held constant. Torsion, control-loop motion, thermal drift, guide pitch and working-point offset are excluded. Add those effects separately where the application requires them; the resulting curves are not a complete machine-position error prediction.

Condition to defineSuggested recordWhy it changes the interpretation
LoadDirection, application point, increment and initial load stateContact stiffness and load paths can change with state
Measurement and referenceThe fixed reference used for carriage displacementDifferent locations include different joints and base deformation
Nut positionx from the left axial support reference, together with total spacing LDefines shaft segment lengths rather than just a machine coordinate
Restraint and controlAxial locating ends, rotational holding, feedback and loading rateSeparates mechanical compliance from rotation or controller motion

Stiffness k = ΔF/Δδ and compliance c = Δδ/ΔF are reciprocals. Using increments makes clear that a slope is being evaluated around a specified preload and contact state. If loading separates a contact, causes slip or enters a strongly nonlinear range, use the appropriate force–displacement relationship instead of extending one constant stiffness indefinitely.

02 / Equivalent paths

Build each series branch before combining the ends

With axial reaction at the left end only, load returns through the nut, left screw segment and left support. A right-end radial support does not automatically provide a second axial path. If both ends are designed to restrain axial displacement, the load at the nut can return through two paths to the same reference structure. They carry load at a common node displacement, so the paths act in parallel.

kL = [1000x/(EA) + 1/kbL]⁻¹
kR = [1000(L−x)/(EA) + 1/kbR]⁻¹

E in N/mm²; A in mm²; x and L in mm; all stiffnesses in N/μm. The factor 1000 converts the shaft segment compliance from mm/N to μm/N.

k_bL and k_bR represent the effective axial stiffness of each support bearing assembly and its local housing connection. Combine each shaft segment in series with its own support to obtain k_L and k_R. A is the selected equivalent axial section. For a stepped shaft, add the segment compliances using their individual lengths and areas rather than using the largest visible diameter throughout.

kend = kL + kR
1/kaxis = 1/kend + 1/kn + 1/kc; δ = F/kaxis

k_n is incremental nut-contact stiffness. k_c is the common nut-bracket/carriage connection stiffness before the load divides. With axial support at the left end only, use k_end = k_L.
Structural partCombinationAvoid counting twice
Left shaft segment and left supportSeries compliance within one branchThe local housing connection already included in k_bL
Right shaft segment and right supportSeries compliance within one branchA radial-only support cannot be added as an assumed axial path
Left and right axial pathsParallel stiffness at their common nodeDo not add the two branch compliances as if they were in series
Nut and common mounting connectionSeries compliance with the end-path networkDo not separately add parts already included in measured assembly stiffness

This network assumes stable end references and branches coupled only through the common node. If base bending moves the two supports, or a plate couples their reactions, add the appropriate base compliance or coupled model. Assigning the same physical plate deformation independently to both branches can count it twice and obscure the actual relationship.

03 / Position example

Compare displacement under the same 600 N increment

Use an independent model with axial support spacing L = 1,000 mm, equivalent solid-rod diameter 16 mm and E = 210,000 N/mm², giving A = 201.06 mm². Assign each end support an effective stiffness of 150 N/μm, the nut contact 180 N/μm and the common connection 120 N/μm. These assumed values explain the network; they are not measurements or ratings for an HZMotion model.

Apply an axial increment F = 600 N and assume the contact state remains unchanged throughout loading. Compare axial support at the left end only with axial support at both ends, keeping the other parameters the same. At x = 500 mm, each shaft segment has stiffness about 84.45 N/μm. In series with a 150 N/μm support, each end branch becomes approximately 54.03 N/μm.

Nut position xSingle-end k_axisSingle-end δDual-end k_axisDual-end δ
200 mm39.54 N/μm15.18 μm45.91 N/μm13.07 μm
500 mm30.87 N/μm19.44 μm43.21 N/μm13.89 μm
800 mm25.31 N/μm23.70 μm45.91 N/μm13.07 μm
Under the assumed 600 N load, displacement with left-end-only axial support increases with distance from that end. The symmetric dual-end model has its largest displacement at midspan: about 13.07, 13.89 and 13.07 micrometres at 200, 500 and 800 mm.
Independent linear incremental model. Both support compliances and the common nut/connection compliances are included. The plotted range x = 150–850 mm is not a product stroke or stiffness specification.

In the single-end model, moving the nut away from the axial locating end lengthens the shaft segment transmitting load and increases its compliance. In the symmetric dual-end model, both ends provide a return path. At midspan neither branch is short, so total stiffness is lowest there and the curve is symmetric. Unequal end-support stiffness would change that symmetry.

At midspan, the two parallel branches give k_end ≈ 108.06 N/μm. After adding nut and common-connection compliance, the complete modeled axis has only about 43.21 N/μm. This explains why improving the supports can yield less overall improvement than a shaft-only calculation suggests: the load still crosses other compliant components.

04 / Load sharing

Support reactions follow stiffness, not an automatic half split

ΔFL = F · kL/(kL+kR)
ΔFR = F · kR/(kL+kR)

These are the magnitudes of the incremental axial loads carried by the two paths. Their sum is F and ΔF_L/k_L = ΔF_R/k_R. Determine tension/compression signs from the free-body diagram.

At x = 200 mm in the example, the shorter, stiffer left path carries about 415.2 N of the increment and the right path about 184.8 N. Only at midspan do they each carry 300 N. This division helps organize support checks, but it is not the complete internal contact load of each bearing. Bearing arrangement, preload and load direction still have to be included.

Initial tensile preload and the incremental force in this model are separate accounting items. Nut-node movement can increase tension in one segment and reduce it in the other, or produce a compression increment under some initial conditions. Combine initial state and increments with consistent signs to determine net tension/compression, maintained contact and bearing loads. Thermal changes in support spacing require an additional calculation.

Replacing the nut with a stiffer configuration does not remove a long single-end shaft path or a flexible mounting connection. Conversely, a stiff support network can still be limited by the nut bracket or carriage attachment. Locate the main displacement contributions before comparing a larger section, different support layout, improved joint or revised measurement reference.

Also distinguish slope from hysteresis. Smooth reversible displacement is consistent with elastic compliance. A direction-dependent loop, drifting zero or discontinuity can require checks for friction, clearance, slip and contact changes. Those effects should not all be hidden inside a single low-stiffness constant.

05 / Measurement

Measure the axis, then separate accessible contributions

At representative nut positions, record axial force and displacement with an agreed loading arrangement. Keep the load point, rotational restraint, temperature, measurement direction and reference consistent. The displacement reference should move as little as possible under load; a bending sensor bracket adds its own compliance to the reading.

Measurement relationshipContribution being investigatedBoundary to record
Carriage relative to fixed referenceTotal axial response under the chosen loading conditionsWhether base, guide and control-loop effects are included
Support housing relative to mounting baseHousing attachment and local base displacementDo not cross an additional undefined flexible path
Shaft end relative to support housingSupport-bearing and shaft-clamping displacementUse an accessible, reliable reference without rotating interference
Opposite sides of the nut-bracket/carriage connectionRelative deformation or slip in the common connectionInstrument only where drawing and access conditions allow
  1. Record the initial stateConfirm assembly, preload and temperature, and use the approved static-load range.
  2. Cover several positionsChoose representative near-end, middle and far-end locations with the same loading arrangement.
  3. Load and unload in stepsRecord actual force and settled displacement at each step, retaining loading direction.
  4. Compare incremental slopesCalculate ΔF/Δδ within the same contact regime; do not fit across a clearance or slip discontinuity.
  5. Return to the structureRelate measured compliance to the actual support, nut and joints before choosing a change and repeating the measurement.

HZMotion actuators and HZM worktables combine screw drive, guides and mounting structure into motion units; support units and nut brackets provide component options. Family names identify structures but do not supply every stiffness needed in this model. Start with the HZM structure description and support-unit catalog, then request model-specific force–displacement or structural information.

Specify allowable displacement at a stated load instead of asking only for “high rigidity.” Include the working-position range, force direction, initial preload, mounting base and measurement reference. Those details let component data be translated into an axis requirement.

06 / Questions

Common axial-stiffness modeling questions

Does fixing both ends make the complete axis four times stiffer?

Not as a general claim. A fourfold ratio can arise for an ideal uniform shaft with rigid axial end supports when particular weakest positions are compared. Support, nut and joint compliance change the improvement of the complete axis.

Why are the two ends not part of one long series chain?

The left and right paths connect the same loaded node to the fixed reference and carry load at the same node displacement, so their stiffnesses add. The shaft segment and support within each path are in series.

Can catalog nut stiffness be used as complete axis stiffness?

No. Establish the stated load, preload and measurement scope, then include the screw, supports and actual connections. If a measured assembly value already includes a component, avoid adding it again.

Can greater preload remove every axial displacement?

No. Preload can change contact state and incremental stiffness while also affecting friction, temperature and internal load. Shaft extension, housing joints and base deformation still require their own evaluation.